haxelib and Stencyl project

Hi,
After some hours spend to got the environment variable in place, I manage to be able to use **haxelib** (I am under Linux, I don't think it is granted).
In order to look at the installed librairies :

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haxelib listto have some info

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haxelib infofor example

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haxelib info tilelayer

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Name: tilelayer
Tags: nme, openfl
Desc: Lightweight wrapper over OpenFL's powerful but lowlevel 'drawTiles', with bitmap-based fallback for Flash. Includes a Sparrow spritesheets parser supporting animations and trimming.
Website: http://github.com/matthewswallace/openfl-tilelayer
License: MIT
Owner: elsassph
Version: 0.2.0
Releases:
   2013-06-07 16:39:21 0.0.1 : This is the first iteration of porting nme-tilelayer to work with Haxe 3 and Openfl
   2014-06-25 10:51:06 0.2.0 : In sync with nme-tilelayer, addition of a test project
 my question :

Why there is no such infos on stencyl and stencyl-cppia ?

Neither of those libraries are actually haxelib packages. That is, we haven't uploaded either of them so that you can simply "haxelib install stencyl", for example. So there isn't really a need to have package info for either of them, since anybody who is using them already knows what they are.

I am not sure to follow you ..
They are not haxelib libraries ..
but I can install them with haxelib ?

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haxelib install stencyl
I did not ask to pleasure to see the number of my posts increasing .
I do find difficult to understand the structure of stencyl .

No, those two are not registered haxelib packages (you can see for yourself by searching stencyl at the haxelib site), and using "haxelib install stencyl" was an example of something that you can't do because of that. Sorry for the poorly worded post.

If you don't understand the structure of Stencyl, that's not really something that would be put into haxelib package info anyway. The best starting point for learning the structure of the Stencyl engine would be stencyl-engine's Code Structure page, but if you want some more info about something specific, feel free to ask.